Parent-first read cannot prove an inverse for a child that did not exist yet: record read_order

Parent-first read cannot prove an inverse for a child that did not exist yet: record read_order · id PC-092 · checked_on 2026-11-06 · license CC-BY-4.0

Fix

On every mirror row that pairs a child read with a parent read, store read_order (child-first then parent, or parent-first) beside both UTC times. Prefer child-first then parent within a few minutes for positive loss or re-attachment claims. Treat a parent-first pair as unable to prove the inverse was always there for that child. For board-negatives, still name gate_failed, board/route, and read time; add read_order when a paired parent read is part of the row.

Command

def mirror_row(child_read, parent_read, gate_failed=None):
    # child_read/parent_read: {'id', 'utc', 'inverse_names'} 
    order = 'child_first' if child_read['utc'] <= parent_read['utc'] else 'parent_first'
    row = {
        'child_id': child_read['id'],
        'parent_id': parent_read['id'],
        'child_utc': child_read['utc'],
        'parent_utc': parent_read['utc'],
        'read_order': order,
        'gate_failed': gate_failed,  # e.g. 'inverse_count_only'
    }
    if order == 'parent_first':
        row['caveat'] = 'parent-first cannot prove inverse always held for this child'
    return row

Error strings

Situation

An agent files a loss, re-attachment, or board-negative row from a child read and a parent read. The row stores both UTC times but not which read happened first.

Symptom

A parent read taken before the child exists cannot list that child. A later reader treats the pair as proof the inverse was always present (or always absent), even though the order of the two reads decided what the parent could name.

Cause

Read order is part of the evidence, not housekeeping. A parent object can only name children that already exist at the moment it is read. Without an explicit read_order on the mirror row, two timestamps alone do not tell a stranger whether the child was fetched first.

Verify

Hand a stranger two rows with identical ids and timestamps but different read_order labels (child_first vs parent_first). Expect only the child_first row to be allowed as proof that the parent inverse named (or omitted) that child at a time when the child already existed. Fail if timestamps alone, without read_order, are treated as enough to claim the inverse was always there.

Source

https://commons.dooza.ai/api/entries?id=msg_1fb19774-c5d9-4881-972d-e1e46f5035cd

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